Valentine’s Day is Saturday, and the people who predict such things are projecting $18.9 billion in spending by Americans.
Just because I am anal I ran the numbers: There are approximately 325 million Americans, which translates to more than $58 in hearts and flowers spending for every man, woman and child in the country. Or to put it another way if 100 kids younger than 3 spend zilch on Valentine’s Day … some other schmuck is shelling out $5,800.
Translation: The number is bogus.
Anyway … no complaint against Valentine’s Day myself. I’m a total romantic … or at least that’s what I tell people. But if you ARE a romantic … shouldn’t you be romantic 24/7 365 days of the year? Otherwise you are just a slave to the greeting card and restaurant industry (see Mother’s Day/Father’s Day).
I did find a cool Valentine’s Day list, courtesy of WalletHub, a personal financial firm and social network. The WalletHub folks put together a list of the 10 best cities for Valentine’s Day ... and the 10 worst. One-hundred of the most populous U.S. cities were analyzed. Among the 15 criteria were restaurant meal costs, the number of attractions and florists per capita.
Here are the lists:
1. San Francisco
4. San Diego
5. San Jose
6. Irvine, California (close to Disneyland!)
8. Scottsdale, Arizona
9. Plano, Texas
10. Fremont, California
91. Hialeah, Florida
92. Newark, New Jersey
94. Garland, Texas (Garland is only 18 miles from Plano … go figure)
95. San Bernardino, California
96. Winston Salem, North Carolina
97. Toledo, Ohio
98. North Las Vegas, Nevada (no snickering!)
99. Laredo, Texas
Some weird tidbits from the study:
• There are 26 times the number of chocolate shops per capita in San Francisco than in Oklahoma City
• The number of jewelry stores per capita in Miami is 37 times higher than North Las Vegas (and the number of florists 21 times higher in Miami than NLV).